sort list based on another list java sort list based on another list java

The answer of riza might be useful when plotting data, since zip(*sorted(zip(X, Y), key=lambda pair: pair[0])) returns both the sorted X and Y sorted with values of X. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. What video game is Charlie playing in Poker Face S01E07? In each iteration, follow the following step . We can use the following methods to sort the list: Using stream.sorted () method Using Comparator.reverseOrder () method Using Comparator.naturalOrder () method Using Collections.reverseOrder () method Using Collections.sort () method Java Stream interface Java Stream interface provides two methods for sorting the list: sorted () method Do roots of these polynomials approach the negative of the Euler-Mascheroni constant? In this tutorial we will sort the HashMap according to value. I see where you are going with it, but you need to rethink what you were going for and edit this answer. I used java 8 streams to sort lists and put them in ArrayDeques. If they are already numpy arrays, then it's simply. However, if we're working with some custom objects, which might not be Comparable by design, and would still like to sort them using this method - we'll need to supply a Comparator to the sorted() call. rev2023.3.3.43278. Once sorted, we've just printed them out, each in a line: If we wanted save the results of sorting after the program was executed, we would have to collect() the data back in a Collection (a List in this example), since sorted() doesn't modify the source. One way of doing this is looping through listB and adding the items to a temporary list if listA contains them: Not completely clear what you want, but if this is the situation: That's right but the solutions use completely different methods which could be used for different applications. I want to sort listA based on listB. In case of Strings, they're sorted lexicographically: If we wanted the newly sorted list saved, the same procedure as with the integers applies here: Check out our hands-on, practical guide to learning Git, with best-practices, industry-accepted standards, and included cheat sheet. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. You can use a Bean Comparator to sort this List however you desire. I need to sort the list of factories based on price of their items and also sort list of other items from competitors for each factory. As each pair of strings are passed in for comparison, convert them into ints using originalList.indexOf, except that if the index is -1, change the index to originalList.size () Compare the two ints. Learn more. (This is a very old answer!). P.S. This method will also work when both lists are not identical: /** * Sorts list objectsToOrder based on the order of orderedObjects. How can I check before my flight that the cloud separation requirements in VFR flight rules are met? Solution based on bubble sort (same length required): If the object references should be the same, you can initialize listA new. Create a Map that maps the values of everything in listB to something that can be sorted easily, such as the index, i.e. 2. Collections.sort() method is overloaded and we can also provide our own Comparator implementation for sorting rules. If you want to do it manually. This is just an example, but it demonstrates an order that is defined by a list, and not the natural order of the datatype: Now, let's say that listA needs to be sorted according to this ordering. Specifically, we're using the comparingInt() method, and supplying the user's age, via the User::getAge method reference. How can this new ban on drag possibly be considered constitutional? How can we prove that the supernatural or paranormal doesn't exist? Then you can create your custom Comparator that uses the Map to create an order: Then you can sort listA using your custom Comparator. @Debacle What operations are allowed on the backend over listA? In Python 2, zip produced a list. Sorting a 10000 items list 100 times improves speed 140 times (265 ms for the whole batch instead of 37 seconds) on my The solution below is simple and should fix those issues: Location of index in list2 is tracked using cur_loclist. Thanks. Why do small African island nations perform better than African continental nations, considering democracy and human development? In Java 8, stream() is an API used to process collections of objects. No spam ever. We've used the respective comparison approaches for the names and ages - comparing names lexicographically using compareTo(), if the age values are the same, and comparing ages regularly via the > operator. Something like this? A tree illustrates a hierarchical structure in contrast to other data structures such an array, stack, queue, and linked list, which are linear in nature. Connect and share knowledge within a single location that is structured and easy to search. Overview. We can use the following methods to sort the list: Java Stream interface provides two methods for sorting the list: Stream interface provides a sorted() method to sort a list. Not the answer you're looking for? If you have 2 lists of identical number of items and where every item in list 1 is related to list 2 in the same order (e.g a = 0 , b = 1, etc.) This class has two parameters, firstName and lastName. But because you also like to be able to sort history based on frequency, I would recommend a History class: Then create a HashMap to quickly fill history, and convert it into a TreeSet to sort: Java List.Add() Unsupportedoperationexception, Keyword for the Outer Class from an Anonymous Inner Class, Org.Hibernate.Hibernateexception: Access to Dialectresolutioninfo Cannot Be Null When 'Hibernate.Dialect' Not Set, Convert Timestamp in Milliseconds to String Formatted Time in Java, How to Query Xml Using Namespaces in Java with Xpath, Convenient Way to Parse Incoming Multipart/Form-Data Parameters in a Servlet, How to Convert the Date from One Format to Another Date Object in Another Format Without Using Any Deprecated Classes, Eclipse 2021-09 Code Completion Not Showing All Methods and Classes, Rotating Coordinate Plane for Data and Text in Java, Java Socket Why Server Can Not Reply Client, How to Fix the "Java.Security.Cert.Certificateexception: No Subject Alternative Names Present" Error, Remove All Occurrences of Char from String, How to Use 3Des Encryption/Decryption in Java, Creating Multiple Log Files of Different Content with Log4J, Very Confused by Java 8 Comparator Type Inference, Copy a Stream to Avoid "Stream Has Already Been Operated Upon or Closed", Overload with Different Return Type in Java, Eclipse: How to Build an Executable Jar with External Jar, Stale Element Reference: Element Is Not Attached to the Page Document, Method for Evaluating Math Expressions in Java, How to Use a Tablename Variable for a Java Prepared Statement Insert, Why am I Getting Java.Lang.Illegalstateexception "Not on Fx Application Thread" on Javafx, What Is a Question Mark "" and Colon ":" Operator Used For, How to Validate Two or More Fields in Combination, About Us | Contact Us | Privacy Policy | Free Tutorials. More elegant code or using some built in Java class? Maybe you can delete one of them. If you have any suggestions for improvements, please let us know by clicking the report an issue button at the bottom of the tutorial. Guava has a ready-to-use comparator for doing that: Ordering.explicit(). I think most of the solutions above will not work if the 2 lists are of different sizes or contain different items. C:[a,b,c]. @Jack Yes, like what I did in the last example. 2. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. The signature of the method is: Let's see another example of Collections.sorts() method. In this tutorial, we will learn how to sort a list in the natural order. Thanks for learning with the DigitalOcean Community. Developed by JavaTpoint. 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Other answers didn't bother to import operator and provide more info about this module and its benefits here. Making statements based on opinion; back them up with references or personal experience. What happens if you have in List1, 50, 40 30 , and in List2 50 45 42? It returns a stream sorted according to the natural order. May be just the indexes of the items that the user changed. Ultimately, you can also just use the comparing() method, which accepts a sorting key function, just like the other ones. The Collections class has two methods for sorting a list: The sort() method sorts the list in ascending order, according to the natural ordering of its elements. I did a static include of. 1. I don't know if it is only me, but doing : Please add some more context to your post. "Sunday" => 0, , "Saturday" => 6. However, some may lead to under-performing solutions if not done properly. I've seen several other questions similiar to this one but I haven't really been able to find anything that resolves my problem. This is an old question but some of the answers I see posted don't actually work because zip is not scriptable. Lets look at an example where our value is a custom object. We first get the String values in a list. I have created a more general function, that sorts more than two lists based on another one, inspired by @Whatang's answer. @RichieV I recommend using Quicksort or an in-place merge sort implementation. There are at least two good idioms for this problem. That way, I can sort any list in the same order as the source list. your map should be collected to a LinkedHashMap in order to preserve the order of listB. The solution below is simple and does not require any imports. How can I randomly select an item from a list? How to remove an element from a list by index, Sorting an array of objects by property values, String formatting: % vs. .format vs. f-string literal. We can easily reverse this order as well, simply by chaining the reversed() method after the comparingInt() call: While Comparators produced by methods such as comparing() and comparingInt(), are super-simple to work with and only require a sorting key - sometimes, the automated behavior is not what we're looking for. How to sort one list and re-sort another list keeping same relation python? I like having a list of sorted indices. Code Review Stack Exchange is a question and answer site for peer programmer code reviews. Please mail your requirement at [emailprotected] Duration: 1 week to 2 week. Found within the Stream interface, the sorted() method has two overloaded variations that we'll be looking into. Does a summoned creature play immediately after being summoned by a ready action? Just remember Zx and Zy are tuples. 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